[VicPiMakers Projects] Jim's Challenge - Output 10 (caesar cipher)

[Craig Miller]

Greg,

I think you are over thinking it. A Cesarian Shift Encryption is pretty
simple. It uses a single number to shift the letters with wrap around at
the end. Here's some more info:
https://en.wikipedia.org/wiki/Caesar_cipher

Or perhaps I have misunderstood the problem, because I went for the simple
answer.

Craig...
-- 
IPv6 is the future!
http://ipv6hawaii.org/


On Sun, Oct 11, 2020 at 8:01 AM Greg H <greg.horie at gmail.com> wrote:

> For me, the confusion is that we're intended to write code to derive the
> cipher key value. I did this and came up with an answer, but this key is
> only relevant "HOUVYE" / "BIOPSY".
>
> So should I take this key and make it a constant for future inputs /
> encryptions? That's what I ended up doing with my final code submission.
>
> I took out the code that solved the problem because unused code seems like
> lint to me, but maybe I should put it back to show how I did it.
>
>
> On Sat, 10 Oct 2020 at 17:45, James Briante <briantej at gmail.com> wrote:
>
>> Hi Patrick,
>>  Yes, you can look at only the first character of the string and use it
>> to get the key. Comparing all characters as the advantage of catching
>> errors in encryption/decryption. The code is just as short using
>> "compare strings"  of your particular language.
>>
>> In C int strcmp (const char* str1, const char* str2);, in C++ *int*
>> *CompareText*(*const* AnsiString *S1*, *const* AnsiString *S2*); Pascal
>> ( Delphi) *function* *CompareText*(*const* *S1*: *string*; *const* *S2*:
>> *string*): Integer;
>>
>> Aside: The purpose of the final test data is to see if your outputs are
>> correct when you run your code with the new data. It should work the first
>> time with no changes in the actual code.
>> Jim
>>
>> On Sat, Oct 10, 2020 at 4:46 PM George Bowden <gtbowdeng at gmail.com>
>> wrote:
>>
>>> Hi Michelle
>>> If you are on a laptop or computer using chrome, you can hold down the
>>> CTRL key and tap the letter u .  There are things further back than that
>>> but its a start.  As for ink marks showing through, we try to avoid that
>>> because it usually reveals security holes that the bad people exploit.
>>>
>>> On Sat, Oct 10, 2020 at 1:23 PM Michelle Wiboltt <
>>> michellewiboltt at outlook.com> wrote:
>>>
>>>> Please help:)
>>>> Here’s where my crazy comes in, see this image...
>>>> [image: Image.jpeg]
>>>> Ok.
>>>>
>>>> Now, if u could think in terms of front back / embroidery and its front
>>>> back...
>>>> So, above is a code interface? But where is the back front and back?
>>>> Front would be the website, right? So, when I do online shopping, that’s
>>>> the front. Where is the back view of the front of the website?
>>>>
>>>> Another example, when writing in ink it can show through the backside
>>>> when held to the light, kind of thing is what I’m trying to understand?
>>>> Where’s that on the internet?
>>>>
>>>> Thx
>>>> m
>>>>
>>>> Michelle Wiboltt
>>>> www.elb1b69.net
>>>> 604-612-2505
>>>>
>>>> ------------------------------
>>>> *From:* Projects <projects-bounces at vicpimakers.ca> on behalf of Greg H
>>>> <greg.horie at gmail.com>
>>>> *Sent:* Saturday, October 10, 2020 8:56:49 AM
>>>> *To:* projects at vicpimakers.ca <projects at vicpimakers.ca>
>>>> *Subject:* [VicPiMakers Projects] Jim's Challenge - Output 10 (caesar
>>>> cipher)
>>>>
>>>> I'm looking for clarification on output 10 - caesar cipher problem.
>>>>
>>>> Is the intent to calculate the caesar cipher key value OR is the intent
>>>> to encrypt the string with a pre-determined key? Initially I thought the
>>>> question was to discover the cipher key value, but on reflection this seems
>>>> fragile.
>>>>
>>>> Reasoning:
>>>> - "BIOPSY" will work for the 12 integer input that leads to "HOUVYE",
>>>> but it will not work for any 12 random integers.
>>>> - You'd have to reverse engineer your integers starting from "BIOPSY"
>>>> to get a valid set of 12 integers.
>>>>
>>>> I solved it both ways, but posted only the 2nd solution to github
>>>> because only the 2nd solution will work for a random set of 12 integers.
>>>>
>>>> I'm curious how other folks solved this one.
>>>>
>>>> --
>>>> Projects mailing list
>>>> Projects at vicpimakers.ca
>>>> http://vicpimakers.ca/mailman/listinfo/projects_vicpimakers.ca
>>>>
>>>
>>>
>>> --
>>> George Bowden, vice president, Victoria Computer Club
>>> gtbowdeng at gmail.com
>>> --
>>> Projects mailing list
>>> Projects at vicpimakers.ca
>>> http://vicpimakers.ca/mailman/listinfo/projects_vicpimakers.ca
>>>
>> --
>> Projects mailing list
>> Projects at vicpimakers.ca
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>>
> --
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